### Can hollow sphere be charged?

## Can hollow sphere be charged?

The conducting hollow sphere is positively charged with +q coulomb charges. If the sphere has equal density all over its surface , then +q charge will be equally distributed all over the surface. As the charges are positive , the sphere will repulse any positive point charge near it .

**What is a thin spherical shell?**

Thin spherical shell is also termed as a pressure vessel and such vessels are usually used in various engineering applications such as for storing the fluid under pressure. Wall thickness of a thin spherical shell will be equal or less than the 1/20 of the internal diameter of shell.

### What is charged spherical shell?

The electric charge distribution over the surface of a spherical shell behaves as if the whole charge were situated at the center of the spherical shell. uniformly charged spherical shell at its surface i.e. �� = ��. Let point P be situated inside the spherical shell at a distance r from the center of the shell.

**What is the charge of a shell?**

Everywhere inside a thin shell of uniform charge, the electric field due to the charge of the shell is 0.

#### Why electric field inside a conductor is zero?

Electric field is zero inside a charged conductor. For a charged conductor, the charges will lie on the surface of the conductor.So, there will not be any charges inside the conductor. When there is no charge there will not be electric field.

**Which stress is the least in a thin shell Mcq?**

This set of Strength of Materials Multiple Choice Questions & Answers (MCQs) focuses on “Thin Cylinders”. Explanation: The thickness of plate is negligible when compared to the diameter of the cylindrical shell, and then it can be termed as a thin cylinder. The radius stress in the cylinder walls is negligible.

## What is volume of hemispherical shell?

Hemispherical shell: Volume of material used for hemispherical shell=23π(R3−r3)

**Why electric field inside a shell is zero?**

It follows that: The electric field immediately above the surface of a conductor is directed normal to that surface. Now, the gaussian surface encloses no charge, since all of the charge lies on the shell, so it follows from Gauss’ law, and symmetry, that the electric field inside the shell is zero.

### Is the electric field in a conductor always zero?

The electric field is zero inside a conductor. Just outside a conductor, the electric field lines are perpendicular to its surface, ending or beginning on charges on the surface. Any excess charge resides entirely on the surface or surfaces of a conductor.

**Is there charge inside a sphere?**

That is, the electric field inside the sphere of uniform charge is zero at the center and increases linearlywith radius r: Of course, the two expressions for the electric field match — have the same value — at the surface of the sphere, for r = a.

#### What charge does a sphere carry?

Sphere 1 has a charge of −4,8×10−18C. Sphere 2 has 60 excess electrons.

**What is the charge density of a spherical shell?**

Electric Field Due to Spherical Shell For a uniformly charged sphere, the charge density that varies with the distance from the centre is: ρ (r) = arⁿ (r ≤ R; n ≤ 0) As the given charge density function symbolizes only a radial dependence with no direction dependence, therefore, it can be a spherically symmetrical situation.

## Why is the field of charged spherical shell larger than the outer radius?

In this case, due to the symmetry of the charge distribution, the vector of electric intensity is at all points perpendicular to the surface and is of the same size. Let us divide this task into three following cases: The radius of the Gaussian sphere is larger than the outer radius of the charged spherical shell.

**Which is larger the Gaussian sphere or the charged shell?**

The radius of the Gaussian sphere is larger than the outer radius of the charged spherical shell. The radius of the Gaussian sphere is smaller than the outer radius and larger than the inner radius of the charged shell. The radius of the Gaussian sphere is smaller than the inner radius of the charged spherical shell.

### How is the field of a charged shell calculated?

Inside it the whole charge is distributed in the shell. The charge is given by the charge density and the volume of the shell. When calculating the intensity field in the charged shell, the radius of the Gaussian sphere is smaller than the outer radius of the shell and greater than the inner radius of the shell.

Can hollow sphere be charged? The conducting hollow sphere is positively charged with +q coulomb charges. If the sphere has equal density all over its surface , then +q charge will be equally distributed all over the surface. As the charges are positive , the sphere will repulse any positive point charge near it .…